To get my solid, I rotated the area between the curves \(y=x\) and \(y=x^2\) around the line \(y=1.25\). I then approximated it by cylindrical shells. The width of each of my shells was 1/16 and the height was \(x^2-x\), where the \(x\)-value was chosen from the right endpoint of each interval.
One of the issues with the print comes from the fact aht the top shell does not connect smoothly to the shell below it. Initially I thought that this resulted from an error in the printer. When I looked at the Cinema 4D file, however, I discovered that the top shell does not make contact with the shell below it because its height is less than 1/16 (the bowl shape is very flat there). Additionally, the shell second from the top does not make contact with the shell below it, but the height difference is not noticable. Another issue with the print was that the leftover supports look bad. The inside of the object was filled with them, and even after clearing out most of the supports, it still looks terrible. We are thinking about printing the object on a different printer, such as the Form Labs printer (which uses stereolithography) or the ProJet 260 (which uses powder), in order to get the inside part of the object to look clean.







When I went to print my object upright I ran into some problems. It seemed that I had forgotten to merge part of the object and it was printing the inner walls upright which resulted in double the print time and cost. I rotated the object so that the slices were parallel to the build bed – this meant the print required supports. It now looked correct in print preview and printed correctly. My final object from this print looked good, but was rough on one side from removing the supports and I knew if I could fix my problems I would be able to print it with a hollow inside and without supports.





I decided to make the entire object in Cinema 4D and not use Mathematica at all. In Cinema4D, under the ‘add cube’ button I selected ‘cylinder’ to add cylinders to my working screen. To make these cylinders the correct dimensions for the disk method I used the calculations described above. I also used the same calculations and numbers to find the coordinates of each cylinder in order to line them up to create the sphere. Each cylinder’s coordinates were based on the center of the object so two of the coordinates were 0, while the third was the \(x-\)value described above. (Precisely which of the \(x,y,z\) coordinates were used depended on the orientation I chose for the cylinders).
